发布日期: 11/15/2021

Get a List of Filenames

To obtain a list of filenames in a specific directory, use the Files In Directory command.

Files In Directory( path, <recursive( 0 | 1 )> );

Both filenames and subdirectory names are returned as shown in the following example:

Files In Directory( "$SAMPLE_DATA" );

{ "2D Gaussian Process Example.jmp", "Abrasion.jmp", ... "Design Experiment", "Detergent.jmp", ... }

Notice that the files within the Design Experiment subdirectory are not included. And only files in the root $SAMPLE_DATA directory are listed.

To return a list of all file names, add the optional recursive(Boolean) argument to Files In Directory:

Files In Directory( "$SAMPLE_DATA", recursive( 1 ) );

{ "2D Gaussian Process Example.jmp", "Abrasion.jmp", ... "Design Experiment/2x3x4 Factorial.jmp", "Design Experiment/Algorithm Data.jmp", ... }

To get the full pathnames, recurse the directories and concatenate the file paths and file names. The following example loops through each file in the $SAMPLE_DATA directory and subdirectories. The file path is concatenated to each file name.

names = Files In Directory( "$SAMPLE_DATA", recursive( 1 ) );
For( i = 1, i <= N Items( names ), i++,
	names[i] = Convert File Path( "$SAMPLE_DATA" ) || names[i]
);
names;

{"/C:/Program Files/SAS/JMP/16/Samples/Data/2D Gaussian Process Example.jmp",

"/C:/Program Files/SAS/JMP/16/Samples/Data/Abrasion.jmp", ... }

The Files in Directory command accepts native and POSIX paths, as well as paths using path variables. See Path Variables for more information about working with paths.

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