b = 7;
x = {1, 2, b, Sqrt( 3 )};
Show( x );
x = {1, 2, b, Sqrt(3)};
To evaluate items in a list, use the Eval List() function.
b = 7;
x = {1, 2, b, Sqrt( 3 )};
c = Eval List( x );
{1, 2, 7, 1.73205080756888}
Consider the following example, where you have a variable called fullMonth that is a list of 12 items.
::fullMonth = {January, February, March, April, May, June, July, August, September, October, November, December};
::abbrevMonth = {Jan, Feb, Mar, Apr, May, Jun, Jul, Aug, Sep, Oct, Nov, Dec};
::dow = {Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday};
::levels = {Very Low, Low, Medium Low, Medium, Medium High, High, Very High};
::feel = {Strongly Disagree, Disagree, Neutral, Indifferent, Agree, Strongly Agree};
::rating = {Failing, Unacceptable, Very Poor, Poor, Bad, Acceptable, Average, Good, Better, Very Good, Excellent, Best};
::mlist = {::fullMonth, ::abbrevMonth, ::dow, ::levels, ::feel, ::rating};
N Items(::fullMonth); // returns 12 because fullMonth has 12 items.
N Items(::mlist[1]); /* returns this message: "N Items() argument must be a list" because ::mlist[1] is a variable (fullMonth) and fullMonth is a list.*/
When you add the Eval() function:
N Items( Eval( ::mlist[1] ) );
12 /* returns 12 because::mlist[1] holds ::fullMonth, and evaluating it
returns ::fullMonth's list.*/
In a loop, you need the Eval() function in the nested loop to evaluate the variable’s contents. For example:
For( g = 1, g <= N Items( ::mlist ), g++,
For( i = 1, i <= N Items(::mlist[g]), i++,
Show( ::mlist[g][i] )
)
);
// returns the message "N Items() argument must be a list."
To fix the problem, add the Eval() function:
::mlist = {::fullMonth, ::abbrevMonth, ::dow, ::levels, ::feel, ::rating};
For( g = 1, g <= N Items( ::mlist ), g++,
For( i = 1, i <= N Items( Eval( ::mlist[g] ) ), i++,
Show( ::mlist[g][i] )
)
);